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gulp-typescript "params" are not compulsory

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See https://github.com/ivogabe/gulp-typescript/blob/v2.9.2/lib/main.ts#L261
This commit is contained in:
Tanguy Krotoff
2015-11-20 21:01:55 +01:00
parent 16134c168d
commit f9a085d839
2 changed files with 9 additions and 3 deletions
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gulp-typescript/gulp-typescript-tests.ts
+6
View File
@@ -54,3 +54,9 @@ gulp.task('scripts', function () {
return gulp.src('lib/*.ts')
.pipe(typescript(tsProject, undefined, typescript.reporter.fullReporter()));
});
gulp.task('default', function () {
return gulp.src('src/**/*.ts')
.pipe(typescript())
.pipe(gulp.dest('built/local'));
});
gulp-typescript/gulp-typescript.d.ts
Vendored
+3 -3
View File
@@ -6,11 +6,11 @@
/// <reference path="../node/node.d.ts"/>
declare module "gulp-typescript" {
function GulpTypescript(params: GulpTypescript.Params, filters?: GulpTypescript.FilterSettings, reporter?: GulpTypescript.Reporter): GulpTypescript.CompilationStream;
function GulpTypescript(params?: GulpTypescript.Params, filters?: GulpTypescript.FilterSettings, reporter?: GulpTypescript.Reporter): GulpTypescript.CompilationStream;
module GulpTypescript {
export function createProject(params: Params): Project;
export function createProject(file: string, params: Params): Project;
export function createProject(params?: Params): Project;
export function createProject(file: string, params?: Params): Project;
export function filter(filters: FilterSettings): CompilationStream;
interface Params {
declarationFiles?: boolean;