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MattAlexMiracle
3dbe0ae1ba
* commented out legacy numerical solver * added comments and task_scheduling for selecting which task to serve to users * removed standalone task weighting * pre-commit hook rerun Co-authored-by: Alexander Mattick <alex.mattick@fau.de>
99 lines
2.8 KiB
Python
99 lines
2.8 KiB
Python
import numpy as np
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from scipy.special import gammaln, psi
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from scipy.stats import dirichlet
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'''
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Legacy numerical solution.
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Should not be used as it is probably broken
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def make_range(*x):
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"""
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constructs leftover values for the simplex given the first k entries
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(0,x_k) = 1-(x_1+...+x_(k-1))
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"""
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return (0, max(0, 1 - sum(x)))
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def relative_entropy(p, q):
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"""
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relative entropy of the two given dirichlet distributions
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"""
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def tmp(*x):
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"""
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First adds the last always forced entry to the input (the last x_last = 1-(x_1+...+x_(N)) )
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Then computes the relative entropy of posterior and prior for that datapoint
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"""
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x_new = np.append(x, 1 - sum(x))
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return p(x_new) * log2(p(x_new) / q(x_new))
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return tmp
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def naive_monte_carlo_integral(fun, dim, samples=10_000_000):
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s = np.random.rand(dim - 1, samples)
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s = np.sort(np.concatenate((np.zeros((1, samples)), s, np.ones((1, samples)))), 0)
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# print(s)
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pos = np.diff(s, axis=0)
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# print(pos)
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res = fun(pos)
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return np.mean(res)
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def infogain(a_post, a_prior):
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raise (
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"""For the love of good don't use this:
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it's insanely poorly conditioned, the worst numerical code I have ever written
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and it's slow as molasses. Use the analytic solution instead.
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Maybe remove
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"""
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)
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args = len(a_prior)
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p = dirichlet(a_post).pdf
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q = dirichlet(a_prior).pdf
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(info, _) = nquad(relative_entropy(p, q), [make_range for _ in range(args - 1)], opts={"epsabs": 1e-8})
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# info = naive_monte_carlo_integral(relative_entropy(p,q), len(a_post))
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return info
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'''
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def analytic_solution(a_post, a_prior):
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"""
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Analytic solution to the KL-divergence between two dirichlet distributions.
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Proof is in the Notion design doc.
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"""
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post_sum = np.sum(a_post)
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prior_sum = np.sum(a_prior)
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info = (
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gammaln(post_sum)
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- gammaln(prior_sum)
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- np.sum(gammaln(a_post))
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+ np.sum(gammaln(a_prior))
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- np.sum((a_post - a_prior) * (psi(a_post) - psi(post_sum)))
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)
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return info
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def uniform_expected_infogain(a_prior):
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mean_weight = dirichlet.mean(a_prior)
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results = []
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for i, w in enumerate(mean_weight):
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a_post = a_prior.copy()
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a_post[i] = a_post[i] + 1
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results.append(w * analytic_solution(a_post, a_prior))
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return np.sum(results)
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if __name__ == "__main__":
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a_prior = np.array([1, 1, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])
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a_post = np.array([1, 1, 20, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10])
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print("algebraic", analytic_solution(a_post, a_prior))
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# print("raw",infogain(a_post, a_prior))
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print("large infogain", uniform_expected_infogain(a_prior))
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print("post infogain", uniform_expected_infogain(a_post))
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# a_prior = np.array([1,1,1000])
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# print("small infogain",uniform_expected_infogain(a_prior))
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