import numpy as np import collections def integral_image(img): """Integral image / summed area table. The integral image contains the sum of all elements above and to the left of it, i.e.: .. math:: S[m, n] = \sum_{i \leq m} \sum_{j \leq n} X[i, j] Parameters ---------- img : ndarray Input image. Returns ------- S : ndarray Integral image/summed area table of same shape as input image. References ---------- .. [1] F.C. Crow, "Summed-area tables for texture mapping," ACM SIGGRAPH Computer Graphics, vol. 18, 1984, pp. 207-212. """ S = img for i in range(img.ndim): S = S.cumsum(axis=i) return S def integrate(ii, start, end, *args): """Use an integral image to integrate over a given window. Parameters ---------- ii : ndarray Integral image. start : tuple of length equal to dimension of ii Coordinates of top left corner of window(s). For multiple windows start may be a tuple of lists, each list containing the starting row, col, ... index i.e ([row_win1, row_win2, ...], [col_win1, col_win2,...], ...), The convention mirrors the NumPy multi-indexing convention. end : tuple of length equal to dimension of ii Coordinates of bottom right corner of window(s). For multiple windows end may be a tuple of lists, each list containing the end row, col, ... index i.e ([row_win1, row_win2, ...], [col_win1, col_win2, ...], ...) The convention mirrors the NumPy multi-indexing convention. args: optional For backward compatibility with versions prior to 0.10 The earlier function signature was `integrate(ii, r0, c0, r1, c1)`, where r0, c0 are int(lists) specifying start coordinates of window(s) to be integrated and r1, c1 the end coordinates. Returns ------- S : scalar or ndarray Integral (sum) over the given window(s). Examples -------- >>> arr = np.ones((5, 6), dtype=np.float) >>> ii = integral_image(arr) >>> integrate(ii, (1, 0), (1, 2)) # sum from (1,0) -> (1,2) [ 3.] >>> integrate(ii, (3, 3), (4, 5)) # sum form (3,3) -> (4,5) [ 6.] >>> integrate(ii, ([1, 3], [0, 3]), ([1, 4], [2, 5])) # sum from (1,0) -> (1,2) and (3,3) -> (4,5) [ 3. 6.] """ rows = 1 # handle input from new input format if len(args) == 0: if isinstance(start[0], collections.Iterable): rows = len(start[0]) start = np.array(start).T end = np.array(end).T # handle deprecated input format else: if isinstance(start, collections.Iterable): rows = len(start) args = (start, end) + args start = np.array(args[:int(len(args)/2)]).T end = np.array(args[int(len(args)/2):]).T total_shape = ii.shape total_shape = np.tile(total_shape, [rows, 1]) # convert negative indices into equivalent positive indices start_negatives = start < 0 end_negatives = end < 0 start = (start + total_shape) * start_negatives + \ start * ~(start_negatives) end = (end + total_shape) * end_negatives + \ end * ~(end_negatives) if np.any((end - start) < 0) : raise IndexError('end coordinates must be greater or equal to start') # bit_perm is the total number of terms in the expression # of S. For example, in the case of a 4x4 2D image # sum of image from (1,1) to (2,2) is given by # S = + ii[2, 2] # - ii[0, 2] - ii[2, 0] # + ii[0, 0] # The total terms = 4 = 2 ** 2(dims) S = np.zeros(rows) bit_perm = 2 ** ii.ndim width = len(bin(bit_perm - 1)[2:]) # Sum of a (hyper)cube, from an integral image is computed using # values at the corners of the cube. The corners of cube are # selected using binary numbers as described in the following example. # In a 3D cube there are 8 corners. The corners are selected using # binary numbers 000 to 111. Each number is called a permutation, where # perm(000) means, select end corner where none of the coordinates # is replaced, i.e ii[end_row, end_col, end_depth]. Similarly, perm(001) # means replace last coordinated by start - 1, i.e # ii[end_row, end_col, start_depth - 1],and so on. # Sign of even permutations is +ve, while those of odd is -ve. # If 'start_coord - 1' is -ve it is labeled bad and not considered in # the final sum. for i in range(bit_perm): # for all permutations # boolean permutation array eg [True, False] for '10' binary = bin(i)[2:].zfill(width) bool_mask = [bit == '1' for bit in binary] sign = (-1)**sum(bool_mask) # determine sign of permutation bad = [np.any(((start[r] - 1) * bool_mask) < 0) for r in range(rows)] # find out bad start rows corner_points = (end * (np.invert(bool_mask))) + \ ((start - 1) * bool_mask) # find corner for each row S += [sign * ii[tuple(corner_points[r])] if(bad[r] == False) else 0 for r in range(rows)] # add only good rows return S