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use np.cross
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@@ -1,26 +1,5 @@
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import numpy as np
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def crossProd(v0,v1):
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"""
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Cross product of 2 vectors
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:param numpy.array v0: vector of length 3
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:param numpy.array v1: vector of length 3
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:rtype: numpy.array
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:return: cross product of v0,v1
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"""
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# ensure both n0, n1 are vectors of length 1
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assert len(v0) == 3, "Length of v0 should be 3"
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assert len(v1) == 3, "Length of v1 should be 3"
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v2 = np.zeros(3,dtype=float)
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v2[0] = v0[1]*v1[2] - v1[1]*v0[2]
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v2[1] = v1[0]*v0[2] - v0[0]*v1[2]
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v2[2] = v0[0]*v1[1] - v1[0]*v0[1]
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return v2
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def rotationMatrixFromNormals(v0,v1,tol=1e-20):
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"""
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Performs the minimum number of rotations to define a rotation from the direction indicated by the vector n0 to the direction indicated by n1.
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@@ -46,7 +25,7 @@ def rotationMatrixFromNormals(v0,v1,tol=1e-20):
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n0dotn1 = n0.dot(n1)
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# define the rotation axis, which is the cross product of the two vectors
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rotAx = crossProd(n0,n1)
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rotAx = np.cross(n0,n1)
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if np.linalg.norm(rotAx) < tol:
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return np.eye(3,dtype=float)
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