Add function to calculate regularly-spaced grid in nD

This commit is contained in:
Juan Nunez-Iglesias
2013-07-02 13:22:12 +02:00
parent a2e32cc90c
commit bb8cfea8c6
2 changed files with 46 additions and 0 deletions
+2
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@@ -11,6 +11,7 @@ if chk < 18: # Use internal version for numpy versions < 1.8.x
else:
from numpy import pad
del numpy, ver, chk
from .regular_grid import regular_grid
__all__ = ['img_as_float',
@@ -23,3 +24,4 @@ __all__ = ['img_as_float',
'view_as_windows',
'pad',
'random_noise']
'regular_grid']
+44
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@@ -0,0 +1,44 @@
import numpy as np
def regular_grid(ar_shape, n_points):
"""Find `n_points` regularly spaced along `ar_shape`.
The returned points (as slices) should be as close to cubically-spaced as
possible.
Parameters
----------
ar_shape : array-like of ints
The shape of the space embedding the grid. `len(ar_shape)` is the
number of dimensions.
n_points : int
The (approximate) number of points to embed in the space.
Returns
-------
slices : list of slice objects
A slice along each dimension of `ar_shape`, such that the intersection
of all the slices give the coordinates of regularly spaced points.
"""
ar_shape = np.asanyarray(ar_shape)
ndim = len(ar_shape)
unsort_dim_idxs = np.argsort(np.argsort(ar_shape))
sorted_dims = np.sort(ar_shape)
space_size = float(np.prod(ar_shape))
if space_size <= n_points:
return [slice(None)] * ndim
stepsizes = (space_size / n_points) ** (1.0 / ndim) * np.ones(ndim)
if (sorted_dims < stepsizes).any():
for dim in range(ndim):
stepsizes[dim] = sorted_dims[dim]
space_size = float(np.prod(sorted_dims[dim+1:]))
stepsizes[dim+1:] = ((space_size / n_points) **
(1.0 / (ndim - dim - 1)))
if (sorted_dims >= stepsizes).all():
break
starts = np.floor(stepsizes/2)
stepsizes = np.round(stepsizes)
slices = [slice(start, None, step) for
start, step in zip(starts, stepsizes)]
slices = [slices[i] for i in unsort_dim_idxs]
return slices