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Test with an analytic and some documentation.
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@@ -11,6 +11,13 @@ Analytic Functions
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:inherited-members:
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.. automodule:: simpegEM.Utils.Ana.FEM
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:show-inheritance:
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:members:
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:undoc-members:
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:inherited-members:
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Sources
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*******
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@@ -27,7 +27,7 @@ class BaseProblemFDEM(Problem.BaseProblem):
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dataPair = DataFDEM
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Solver = SimpegSolver
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solverOpts = {'doDirect':True, 'options':{'factorize':False, 'backend':'scipy'}}
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solverOpts = {}
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####################################################
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# Mass Matrices
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@@ -110,8 +110,6 @@ class ProblemFDEM_e(BaseProblemFDEM):
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solver = self.Solver(A, **self.solverOpts)
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e = solver.solve(rhs)
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print np.linalg.norm(A*Utils.mkvc(e) - Utils.mkvc(rhs)) / np.linalg.norm(Utils.mkvc(rhs))
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F[freq, 'e'] = e
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b = -1./(1j*omega(freq))*self.mesh.edgeCurl*e
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F[freq, 'b'] = b
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@@ -224,8 +222,6 @@ class ProblemFDEM_b(BaseProblemFDEM):
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#Note that we are solving for b_s
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b = solver.solve(rhs)
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print np.linalg.norm(A*Utils.mkvc(b) - Utils.mkvc(rhs)) / np.linalg.norm(Utils.mkvc(rhs))
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F[freq, 'b'] = b
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e = self.MeSigmaI*self.mesh.edgeCurl.T*self.MfMui*b
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F[freq, 'e'] = e
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@@ -0,0 +1,77 @@
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import unittest
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from SimPEG import *
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import simpegEM as EM
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from scipy.constants import mu_0
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plotIt = False
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class FDEM_analyticTests(unittest.TestCase):
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def setUp(self):
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cs = 10.
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ncx, ncy, ncz = 8, 8, 8
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npad = 5
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hx = Utils.meshTensors(((npad,cs), (ncx,cs), (npad,cs)))
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hy = Utils.meshTensors(((npad,cs), (ncy,cs), (npad,cs)))
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hz = Utils.meshTensors(((npad,cs), (ncz,cs), (npad,cs)))
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mesh = Mesh.TensorMesh([hx,hy,hz], x0=[-hx.sum()/2.,-hy.sum()/2.,-hz.sum()/2.,])
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model = Model.LogModel(mesh)
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x = np.linspace(-10,10,5)
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XYZ = Utils.ndgrid(x,np.r_[0],np.r_[0])
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rxList = EM.FDEM.RxListFDEM(XYZ, 'Ex')
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Tx0 = EM.FDEM.TxFDEM(np.r_[0.,0.,0.], 'VMD', 1e2, rxList)
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survey = EM.FDEM.SurveyFDEM([Tx0])
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prb = EM.FDEM.ProblemFDEM_b(model)
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prb.pair(survey)
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prb.Solver = Utils.SolverUtils.DSolverWrap(sp.linalg.splu, checkAccuracy=False)
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sig = 1e-1
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sigma = np.ones(mesh.nC)*sig
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sigma[mesh.gridCC[:,2] > 0] = 1e-8
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m = np.log(sigma)
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self.prb = prb
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self.mesh = mesh
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self.m = m
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self.Tx0 = Tx0
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self.sig = sig
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def test_Transect(self):
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print 'Testing Transect for analytic'
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u = self.prb.fields(self.m)
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bfz = self.mesh.r(u[self.Tx0, 'b'],'F','Fz','M')
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x = np.linspace(-55,55,12)
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XYZ = Utils.ndgrid(x,np.r_[0],np.r_[0])
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P = self.mesh.getInterpolationMat(XYZ, 'Fz')
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an = EM.Utils.Ana.FEM.hzAnalyticDipoleF(x, self.Tx0.freq, self.sig)
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diff = np.log10(np.abs(P*np.imag(u[self.Tx0, 'b']) - np.abs(mu_0*np.imag(an))))
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if plotIt:
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import matplotlib.pyplot as plt
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plt.plot(x,np.log10(np.abs(P*np.imag(u[self.Tx0, 'b']))))
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plt.plot(x,np.log10(np.abs(mu_0*np.imag(an))), 'r')
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plt.plot(x,diff,'g')
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plt.show()
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# We want the difference to be an orderMag less
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# than the analytic solution. Note that right at
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# the source, both the analytic and the numerical
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# solution will be poor. Use plotIt up top to see that...
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orderMag = 1.6
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passed = np.abs(np.mean(diff - np.log10(np.abs(mu_0*np.imag(an))))) > orderMag
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self.assertTrue(passed)
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if __name__ == '__main__':
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unittest.main()
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@@ -2,9 +2,24 @@ import numpy as np
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from scipy.constants import mu_0, pi
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from scipy.special import erf
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def hzAnalyticDipoleF(r, freq, sigma):
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def hzAnalyticDipoleF(r, freq, sigma, secondary=True):
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"""
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4.56 in Ward and Hohmann
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.. plot::
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import matplotlib.pyplot as plt
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import simpegEM as EM
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freq = np.logspace(-1, 6, 61)
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test = EM.Utils.Ana.FEM.hzAnalyticDipoleF(100, freq, 0.001, secondary=False)
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plt.loglog(freq, abs(test.real))
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plt.loglog(freq, abs(test.imag))
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plt.title('Response at $r$=100m')
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plt.xlabel('Frequency')
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plt.ylabel('Response')
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plt.legend(('real','imag'))
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plt.show()
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"""
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r = np.abs(r)
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k = np.sqrt(-1j*2.*np.pi*freq*mu_0*sigma)
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@@ -13,5 +28,11 @@ def hzAnalyticDipoleF(r, freq, sigma):
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front = m / (2. * np.pi * (k**2) * (r**5) )
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back = 9 - ( 9 + 9j * k * r - 4 * (k**2) * (r**2) - 1j * (k**3) * (r**3)) * np.exp(-1j*k*r)
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hz = front*back
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hp =-1/(4*np.pi*r**3)
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return hz-hp
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if secondary:
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hp =-1/(4*np.pi*r**3)
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return hz-hp
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return hz
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